9^2x+1=(1/3)^3x-2

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Solution for 9^2x+1=(1/3)^3x-2 equation: 



9^2x+1=(1/3)^3x-2

We move all terms to the left:

9^2x+1-((1/3)^3x-2)=0



Domain of the equation: 3)^3x-2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

9^2x-((+1/3)^3x-2)+1=0

We multiply all the terms by the denominator


9^2x*3)^3x-2)-((+1*3)^3x-2)+1=0

We add all the numbers together, and all the variables

9^2x*3)^3x-2)-(3^3x-2)+1=0

Wy multiply elements

27x^3=0

We do not support expression: x^3

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